EduRev JEE Question is disucussed on EduRev Study Group by 185 JEE StudentsCancel (x 1) length = 2x 3 units The synthetic division method is in the attached pictureThe area of the region between the curves is defined as the integral of the upper curve minus the integral of the lower curve over each region The regions are determined by the intersection points of the curves This can be done algebraically or graphically Integrate to find the area between and
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2x y=2 2y-x=4. what is the area of the triangle formed by these lines and the x-axis
2x y=2 2y-x=4. what is the area of the triangle formed by these lines and the x-axis-In graph we find that the lines are intersecting at (1, 4) Hence x = 1, y = 4 is the solution of the equationsThe two triangles are ABC and DBE Area of ABE = × Base × perpendicular Area of ADC = × Base × perpendicular ABE area ADC Area The triangular region bounded by the lines y=2x1, y=3x1 and x=4 is represented graphically as Equations of the lines are y=2x1,y=3x1 and x4 Let y 1 =2x 1, y 2 = 3x1 Now area of the triangle bounded by the given lines = 8 square units Thus, the area of the required triangular region is 8 sq units
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A line that runs parallel to the \(x\)axis is called a horizontal line and has a gradient of zero This is because there is no vertical change \m = \frac{\text{change in } y}{\text{change in } x} = \frac{0}{\text{change in } x} = 0\ A line that runs parallel to the \(y\)axis is called a vertical line and its gradient is undefined What is the area of triangle formed by line 2x3y=12 with the coordinate axes?Solution Question 39 Draw the graphs of the following equations x y — 5;
The zeros are 4 and 12 Function 2 and 3 intersect in P (0,4) 61E Exercises for Section 61 For exercises 1 2, determine the area of the region between the two curves in the given figure by integrating over the xaxis For exercises 3 4, split the region between the two curves into two smaller regions, then determine the area by integrating over the xOf the tetrahedron The base is the triangle in the xyplane sketched below What's the equation for the line?
In Geometry, a triangle is a threesided polygon that has three edges and three vertices The area of the triangle is the space covered by the triangle in a twodimensional plane The formula for the area of a triangle is (1/2) × base × altitude Let's find out the area of a triangleThe area of the triangle formed by the lines 3x 2y = 8, 2x y = 1 and the xaxis has to be determined First, determine the point of intersection of the lines 3x 2y = 8 and 2x y = 1Solve the Following System of Equations Graphically 2x = 23 3y 5x = 8y Also, Find the Area of the Triangle Formed by These Lines and Xaxis in Each Graph
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Question A triangle is formed by the intersection of the lines 2x 3y = 14 4X 5y= 16 and the x axisFind the area of the triangle Thank you so much Answer by ReadingBoosters(3246) (Show Source) Clearly, we can scale the coefficients of a given linear equation by any (nonzero) constant and the result is unchanged Therefore, by dividingthrough by $\sqrt{a_i^2b_i^2}$, we may assume our equations are in "normal form"The area of the triangle formed the lines x=3, y=4 and x=y is MCQ Chapter 3 RD Class 10 🔥🔥 The area of the triangle formed the lines x=3, y=4 and x=y is MCQ Chapter 3
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math 1)The area A of a triangle varies jointly as the lengths of its base b and height h If A is 75 when b=15 and h=10,find A when b=8 and h=6 2)Determine the equation of any vertical asymtotes of the graph of f (x)=2x3/x^22x3 1)X − 2 = 0 x 2 = 0 Add 2 2 to both sides of the equation x = 2 x = 2 x = 2 x = 2 The final solution is all the values that make x ( x − 2) = 0 x ( x 2) = 0 true x = 0, 2 x = 0, 2 x = 0, 2 x = 0, 2 x = 0, 2 x = 0, 2 Substitute 0 0 for x x into y = 2 x y = 2 x then solve for y y Given 2xy=2 , 2yx=4 To Find the area of a triangle formed by the two lines and the line y=0 Solution 2xy=2 2yx=4 y = 0 2xy=2 , y = 0 => point of intersection ( 1 , 0) 2yx=4 , y = 0 => point of intersection ( 4 , 0) 2xy=2 , 2yx=4 => point of intersection ( 0 , 2) Triangle is formed with base = ( 1 (4) = 5 Height = 2
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🔴 Answer 3 🔴 on a question The area of a triangle is 1/2 (x^2 2x 2x^2 4) the height h is x2 write an expression for the base b of the triangle ( hint area of a triangle 1/2 bh) the answers to ihomeworkhelperscom Given 2xy=2 , 2yx=4 To Find the area of a triangle formed by the two lines and the line y=0 Solution 2xy=2 2yx=4 y = 0 2xy=2 , y = 0 => point of intersection ( 1 , 0) 2yx=4 , y = 0 => point of intersection ( 4 , 0) 2xy=2 , 2yx=4 => point of intersection ( 0 , 2) Triangle is formed with base = ( 1 (4) = 5 Height = 2 asked in Class X Maths by saurav24 Expert (14k points) Draw the graph of the pair of equations 2x y= 4 and 2x – y = 4 Write the vertices of the triangle formed by these lines and the yaxis, find the area of this triangle?
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Xy = 5 (i) Find the solution of the equations from the graph (ii) Shade the triangular region formed by the lines and theyaxis Solution 10Answer 2xy = 4(i) ⇒ y = 4−2x If x= 0,y = 4−2(0)= 4−0 =4 x = 1,y = 4−2(1) = 4−2= 2 x = 2,y = 4−2(2) = 4−4= 0 x 0 1 2 3 y 4 2 0 −2 (i) A B C −2If 2x^23xyy^2=0 represents two sides of a triangle and lxmyn=0 in the third side then locus of incentre of the triangle is
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2x y = 2;' pair of linear equations in two variables Solve graphically 2x y = 2 and 4x y = 4, shade the region between these lines and the yaxis Asked by Topperlearning User 31st Aug, 17, 0335 PM Expert Answer
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Well, this is the line with z= 0, so 2x 4y= 8, which amounts to y= 2 x 2 From the picture, we can see that xgoes from 0 to 4 For a given value of x, ygoes from 0 to 2 xHere, the line 2xy=2 cuts the xaxis at (–4,0) and line 2y–x=4 cuts the xaxis at (1,0) and point of intersection of these lines is (0,2) So, the points (–4,0), (0,2) & (1, 0) formed a triangle in which point point (0, 2) lie on yaxis , ie 2 units hight from origin and points (4,0) & (1, 0) lie on xaxis in which distance between these 1(4) =14 = 5 units To calculate the Area at first we solve the Equation 1 & 2 Simultaneously by method of substitution We substitute the value of x from Equation 2 in Equation 1 to get the value of y Equation 2 x – y = 1 ⇒ x = y 1 Equation 1 2x 3y = 12 Substituting the value from equation 2 we get 2(y 1) 3y = 12 ⇒ 2y 2 3y = 12 ⇒ 5y = 10 ⇒ y = 2
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2yx = 4 What is the area of the triangle formed by the two lines and the liney = 0?SolutionShow Solution y = 2 – 2x (i) Now, plot the points A (0, 2), B (1, 0) and C (2, 2) on a graph paper and join A, B and C to get the graph of 2x y = 2 y = 6 – 2x (ii) Now, plot the points D (0,6), E (1, 4) and F (3,0) on the same graph paper and join D, E and F to get the graph of 2xA triangle is formed by the xaxis and the lines 2x y = 4 and x y 1 = 0 as three sides Taking the side along xaxis as its base, the corresponding altitude of the triangle is 3 units
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Explanation Circle 1 x2 y2 6x = 0, ⇒ center C1 = ( −3,0),r1 = 3, Circle 2 x2 y2 −2x = 0, ⇒ center C2 = (1,0),r2 = 1 As the two circles touch each other externally, they have 3 common tangents Obviously, Yaxis (x = 0) is one of the common tangents Let y = mx c be the equation of the other tangents What is the area, in square units, of the triangle bounded by y=0, y=x4 and x3y=12 ?RD Sharma Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations In Two Variables Exercise 32 The knowledge of the construction of graphs of linear equations in solving systems of simultaneous linear equations in two variables is practised in this exercise The RD Sharma Solutions Class 10 can be a great help for students for
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The given pair of straight lines is 2 xy4 = 0 and x y 1 = 0 As, the area formed by the triangle formed by these lines with the xaxis is to be found Solving the equations of lines for y = 0, we get their points of intersection with the xaxis as B 2, 0 and C1, 0 respectively1Graphically, solve the following pair of equations 2x y = 6 and 2x y 2 Find the ratio of the areas of the two triangles formed by the lines representing these equations with the Xaxis and the lines with the Yaxis Ans 41 2Determine graphically, the vertices of the triangle formed by the lines y =3, x = 3y, and x y = 8 We join D,E and F and extend it on the both sides to obtain the graph of the equation 2x y 2 = 0 It is evident from the graph that the two lines intersect at point F (1,4) The area enclosed by the given lines and xaxis is shown in Fig above Thus, x = 1, y = 4 is the solution of the given system of equations
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Jun 14,21 The area of triangle formed by the lines y = x, y = 2x and y = 3x 4 isa)8b)7c)4d)9Correct answer is option 'C' Can you explain this answer? The volume of the solid generated by y = 2x, y = x^2 revolved about the xaxis is (64pi)/15 Revolving the area between these two curves about the xaxis, we end up with something that looks sort of like a cone a hollow cone, with a curved inside Now, imagine for a second taking a cross section parallel to the yz plane, cutting the cone down the middleFind the area of the region bounded by lines 2x y = 4, 3x – 2y = 6 Using the method of integration
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2 4 5 Obtuse scalene triangle, area=38 Computed angles, perimeter, medians, heights, centroid, inradius and other properties of this triangle The area of a rectangle have the formula A = lw To find the length of the given triangle, divide the area by the width There are several ways to do this, so I'll be using synthetic division and cancellation;Factor out the trinomial;
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0 2 We plot the points (2, 0) and (0, 2) on the same graph paper and join the same by a ruler to get the line which is the graph of the equation x y = 2 From graph, we see that the coordinates of the vertices of the triangle are (2, 0), (0, 2) and (0, –4) The triangle has been shadedHere, the line 2xy=2 cuts the xaxis at (–4,0) and line 2y–x=4 cuts the xaxis at (1,0) and point of intersection of these lines is (0,2) So, the points (–4,0), (0,2) & (1, 0) formed a triangle in which point point (0, 2) lie on yaxis , ie 2 units hight from origin and points (4,0) & (1, 0) lie on xaxis in which distance between these 1(4) =14 = 5 unitsWas asked on View the answer now
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Misc 14 Using the method of integration find the area of the region bounded by lines 2𝑥 𝑦 = 4, 3𝑥–2𝑦=6 and 𝑥–3𝑦5=0 Plotting the 3 lines on the graph 2𝑥 𝑦 = 4 3𝑥 – 2𝑦 = 6 𝑥 – 3𝑦 5 = 0 Find intersecting Points A & B Point A Point A is intersection of lines x – 3y 5Question Find the area of the triangle formed by the (x,y)axes and the line with equation 4x3y12=0 Answer by KMST(52) ( Show Source ) You can put this solution on YOUR website! Consider, 2x 3y = 12 Consider, x – y – 1 = 0 Let's plot the graph now From the figure, notice that the base of the triangle = 5 units Altitude = 2 units Hence area of triangle = (1/2) × 5 × 2 = 5 sq units Recommend (0) Comment (0) person Kishore Kumar
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If area of the triangle formed by (0, 0), (a^ (x^2), 0), (0, a^ (6x)) is 1/ (2a^5) sq units then x= This browser does not support the video element Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams The area of the triangle formed by the lines and isSo, AOQD is formed by these lines Hence, the vertices of the A00D formed by the given lines are0(0, 0),Q(4, 4)and 0(6,2) Question 3 Draw the graphs of the equations x = 3, x = 5 and 2x – y – 4 = 0 Also find the area of the quadrilateral formed by the lines and the Xaxis SolutionCorrect answer to the question Draw the graph representing the equations xy=1 and 2x 3y = 12 on the same graph paper , find the area of the triangles formed by theselines, the xaxis and the yaxis brainsanswersincom
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Solution A line through (5, 2) and (1, 4) is perpendicular to the line through Solution The line 2x–3y2=0 is perpendicular to another line L1 of unknown equation Solution Determine B such that 3x2y–7=0 is perpendicular to 2x–By2=0The triangle form by the graph of 2xy=4 and xy=2 and y axis (i) Find the point of intersection of two lines(ii) Write the coordinates of vertices of the triangle(iii) Find the area of triangle(iv) Write the formula of area of triangle which you use for this problems
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